(1/2)x^2-(1/4)x-(3/2)=0

Solution for (1/2)x^2-(1/4)x-(3/2)=0 equation:

(1/2)x^2-(1/4)x-(3/2)=0


Domain of the equation: 2)x^2!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x^2-(+1/4)x-(+3/2)=0

We multiply parentheses

-x^2+(+1/2)x^2-(+3/2)=0

We get rid of parentheses

-x^2+(+1/2)x^2-3/2=0

We calculate fractions


-x^2=0

We add all the numbers together, and all the variables

-1x^2=0

a = -1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-1)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-2}=0$